(x+2)^2=3x+6.

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Solution for (x+2)^2=3x+6. equation: 



(x+2)^2=3x+6.

We move all terms to the left:

(x+2)^2-(3x+6.)=0

We add all the numbers together, and all the variables

(x+2)^2-(3x+6)=0

We get rid of parentheses

(x+2)^2-3x-6=0

We add all the numbers together, and all the variables

-3x+(x+2)^2-6=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+2)^2=6

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